b^2=14-5b

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Solution for b^2=14-5b equation:


Simplifying
b2 = 14 + -5b

Solving
b2 = 14 + -5b

Solving for variable 'b'.

Reorder the terms:
-14 + 5b + b2 = 14 + -5b + -14 + 5b

Reorder the terms:
-14 + 5b + b2 = 14 + -14 + -5b + 5b

Combine like terms: 14 + -14 = 0
-14 + 5b + b2 = 0 + -5b + 5b
-14 + 5b + b2 = -5b + 5b

Combine like terms: -5b + 5b = 0
-14 + 5b + b2 = 0

Factor a trinomial.
(-7 + -1b)(2 + -1b) = 0

Subproblem 1

Set the factor '(-7 + -1b)' equal to zero and attempt to solve: Simplifying -7 + -1b = 0 Solving -7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1b = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1b = 0 + 7 -1b = 0 + 7 Combine like terms: 0 + 7 = 7 -1b = 7 Divide each side by '-1'. b = -7 Simplifying b = -7

Subproblem 2

Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2

Solution

b = {-7, 2}

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